Let m_{1} be the mass of earth, |

Let m_{2} be the mass of moon, |

Let d be the distance between earth and moon, so that d_{1} + d_{2} = d, where d_{1} is the distance of effective gravitational attraction of earth towards moon and d_{2} be the distance of effective gravitational attraction of moon towards earth. |

**Then the distances d**_{1} and d_{2} may be calculated by the formula given below:- |

m_{1}/ m_{2} = d_{1}/ d_{2} |

(Mass of earth is 80 times larger than that of moon and d_{1} is d - d_{2} where d = 384000 kms). ie |

80/1 = (384000 – d_{2})/d_{2} |

80d_{2} = 384000 – d_{2} |

81d_{2} = 384000 |

d_{2} = 384000/81 |

= 4741 kms. |

In the year 1967, I had calculated the above facts regarding sun and earth and had found the formula to be satisfactory. When America explored moon in 1969, I ascertained the above formula to be correct with reference to earth and moon also; because papers had reported that the crew of the spaceship began to feel the gravitational attraction of moon when they reached at a distance of about 5000 kms away from moon. [In the voyage of the spaceship from earth to moon the crew felt the fulcrum only at a distance of d_{2} from moon and not at a distance of d_{2} from earth. So, formulae of Kepler and Newton regarding the calculation of common centre of masses at d_{2} from earth (both had said and everybody believed that the common centre of masses is somewhere at a point near to earth) practically fail and hence the application of their formula for the common centre of masses goes wrong while the new formula proves that there is a balancing wheel only at a distance of d_{2} from moon and that there is a free zero concentration of gravitational forces at the centre of earth and moon and also at the centre of mass of each rotating heavenly body]. |